Problems on Trains ( 6 to 10 )

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Problems on Trains ( 6 to 10 ):


APTITUDE QUESTIONS (PROBLEMS ON TRAINS):

6. A train runs at the speed of 90 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the train?

A)    330 m

B)    340 m

C)    360 m

D)    400 m

E)    None of these

View Answer

Answer: option D

Explanation:

Speed = (90 * 5/18) m/sec = 25 m/sec; Time = 26 sec

Let the length of the train be x metres.

Then, (x+250) / 26 = 25 <=> x + 250 = 650 <=> x = 400

 

7. The length of a train and that of a platform are equal. If with a speed of 72 kmph the train crosses the platform in 1 minute, then the length of the train is:

A)    500

B)    600

C)    750

D)    900

E)    None of these

View Answer

Answer: option B

Explanation:

Speed = (72 * 5/18) m/sec = 20 m/sec; Time = 1 min = 60 sec

Let the length of the train and that of platform be x metres.

Then, 2x/60 = 20 <=> x = 20*60/2 = 600

 

8. A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?

A)    120 m

B)    240 m

C)    300 m


D)    280 m

E)    None of these

View Answer

Answer: option B

Explanation:

Speed = (54 * 5/18) m/sec = 15 m/sec

Length of the train = (15 * 20) m = 300 m

Let the length of the platform be x metres

Then, (x+300) / 36 = 15 <=> x + 300 = 540 <=> x = 240 m

 

9. A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:

A)    50 m

B)    150 m

C)    200 m

D)    250 m

E)    None of these

View Answer

Answer: option B

Explanation:

Let the length of the train be x metres and its speed be y m/sec.

Then, x/y = 15 => y = x/15

∴ (x+100) / 25 = x/15 <=> x = 150 m

 

10. A train takes 18 seconds to pass completely through a station 162 m long and 15 seconds through another station 120 m long. The length of the train is:

A)    70 m

B)    80 m

C)    90 m

D)    100 m

E)    None of these

View Answer

Answer: option C

Explanation:

Let the length of the train be x metres.

∴ (x+162) / 18 = (x+120) /15 <=> 15(x + 162) = 18(x + 120) <=> x = 90m

 

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