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Problems on Ages ( 16 to 20 ):

# APTITUDE QUESTIONS (PROBLEMS ON AGES):

16. One year ago, Preeti was four times as old as her daughter Sakshi. Six years hence, Preeti’s age will exceed her daughter’s age by 9 years. The ratio of the present ages of Preeti and her daughter is:

A) 9:2

B) 11:3

C) 12:5

D) 13:4

E) None of these

View Answer

Answer is D

Explanation:

Let the ages of Preeti and Sakshi 1 year ago be 4x and x years respectively.

Then, [(4x – 1) + 6] – [(x – 1) + 6] = 9 <=> 3x = 9 <=> x = 3

∴ required ratio = (4x + 1) : (x + 1) = 13 : 4

17. The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A?

A) 12

B) 24

C) 18

D) 20

E) None of these

View Answer

Answer is A

Explanation:

(A + B) – (B + C) = 12 <=> A – C = 12

18. The age of a man is three times the sum of the ages of his two sons. Five years later, his age will be double of the sum of the ages of his sons. The father’s present age is:

A) 40

B) 45

C) 50

D) 55

E) None of these

View Answer

Answer is B

Explanation:

Let the sum of present ages of the two sons be x years.

Then, father’s present age = 3x years.

∴ (3x + 5) = 2(x + 10) <=> 3x + 5 = 2x + 20 <=> x = 15

Hence, father’s present age = 45 years.

19. Hitesh is 40 years old and Ronnie is 60 years old. How many years ago was the ratio of their ages 3:5?

A) 5 years

B) 10 years

C) 20 years

D) 37 years

E) None of these

View Answer

Answer is B

Explanation:

Suppose, the ratio was 3:5, x years ago.

Then, (40-x)/(60-x) = (3)/(5) <=> 5(40 – x) = 3(60 – x) <=> 2x = 20 <=> x = 10 years

20. A person’s present age is two-fifth of the age of his mother. After 10 years, he will be one-half of the age of his mother. How old is the mother at present?

A) 32 years

B) 36 years

C) 50 years

D) 48 years

E) None of these

View Answer

Answer is C

Explanation:

Let the mother’s present age be x years. Then, the person’s present age = ((2)(5)x) years.

∴ ((2/5)x+10) = (1/2) (x + 10) <=> 2(2x + 50) = 5(x + 10) <=> x = 50