Prev Next
Problems on Ages ( 11 to 15 ):
APTITUDE QUESTIONS (PROBLEMS ON AGES):
11. The present ages of three persons are in proportions 4 : 7: 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
A) 8, 20, 28
B) 16, 28, 36
C) 20, 35, 45
D) 23, 35, 48
E) None of these
View Answer
Answer is B
Explanation:
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x – 8) + (7x – 8) + (9x – 8) = 56 <=> 20x = 80 x = 4
∴ Their present ages are 16, 28 and 36 years respectively.
12. The ratio between present ages of A and B is 5 : 3 respectively. The ratio between A’s age 4 years ago and B’s age 4 years hence is 1 : 1. What is the ratio between A’s age 4 years hence and B’s age 4 years ago?
A) 2 : 3
B) 2 : 1
C) 3 : 1
D) 4 : 1
E) None of these
View Answer
Answer is C
Explanation:
Let the present ages of A and B be 5x and 3x respectively.
Then, (5x-4)/(3x+4) = (1)/(1) <=> 5x – 4 = 3x + 4 <=> 2x = 8 <=> x = 4
∴ Required ratio = (5x + 4) : (3x – 4) = 24 : 8 = 3:1
13. X is two years older than Y who is twice as old as Z. If the total of the ages of X, Y and Z be 22, then how old is Y?
A) 12
B) 8
C) 14
D) 10
E) None of these
View Answer
Answer is B
Explanation:
Let Z’s age be x years. Then, Y’s age = 2x years. X’s age = (2x + 2) years.
∴ (2x + 2) + 2x + x = 22 <=> 5x = 22 <=> x = 4
Hence, Y’s age = 2x = 8 years.
14. Eighteen years ago, a father was three times as old as his son and now the father is only twice as old as his son. Then what is the sum of the present ages of the son and the father is?
A) 54
B) 72
C) 105
D) 108
E) None of these
View Answer
Answer is D)
Explanation:
Let us consider the present ages of the father and son be 2x and x years respectively.
Then, (2x – 18) = 3(x – 18) <=> x = 36
∴ Required sum = (2x + x) = 3x = 108 years
15. The age of father 10 years ago was thrice the age of his son. Ten years hence, father’s age will be twice that of his son. The ratio of their present ages is:
A) 4: 2
B) 7: 3
C) 9:2
D) 13: 4
E) None of these
View Answer
Answer is B
Explanation:
Let us consider the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) +10 = 2[(x + 10) + 10] <=> 3x + 20 = 2x + 40 <=> x = 20
Hence, required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3