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**Problems on Ages:**

# Aptitude Questions:

1. Sanjay is younger than Raj by 4 years. If their ages are in the respective ratio of 7:9, how old Sanjay is?

A) 14 years

B) 18 years

C) 28 years

D) 24.5 years

E) None of these

View Answer

Answer is D

Explanation:

Let Raj’s age be x years. Then, Sanjay’s age = (x – 7) years

∴ (x-7)/x = (7/9) <=> 9x – 63 = 7x <=> 2x = 63 <=> x = 31.5

Hence, Sanjay’s age = (x – 7) = 24.5 years

2. The ratio between the present ages of X and Y is 5:7 respectively. If the difference between Y’s present age and X’s age after 6 years is 2, what is the total of X’s and Y’s present ages?

A) 48 years

B) 52 years

C) 56 years

D) 60 years

E) None of these

View Answer

Answer is A

Explanation:

Let the present ages of X and Y be 5x years and 7x years respectively.

Then, 7x – (5x + 6) = 2 <=> 2x = 8 <=> x = 4

∴ Required sum = 5x + 7x = 12x = 48 years.

3. Present ages of X and Y are in the ratio 5:6 respectively. Seven years hence this ratio will become 6:7 respectively. What is X’s present age in years?

A) 35

B) 42

C) 49

D) 54

E) None of these

View Answer

Answer is A

Explanation:

Let the present ages of X and Y be 5x years and 6x years respectively.

Then, (5x+7)/(6x+7) = (6/7) <=> 7(5x + 7) = 6(6x + 7) <=> x = 7

∴ X’s present age = 5x = 35 years.

4. Eight years ago, the ratio of the ages of K and S was 7:6. Four years hence, the ratio of their ages will be 11:10. What is S’s age at present?

A) 26 years

B) 28 years

C) 20 years

D) 24 years

E) None of these

View Answer

Answer is A

Explanation:

Let the ages of K and S 8 years ago be 7x and 6x years respectively.

Then, ((7x+8)+ 4) / ((6x+8)+ 4)) = (11/10) <=> 10(7x + 12) = 11(6x + 12) <=> 4x = 12 x = 3

∴ S’s present age = (6x + 8) = 26 years.

5. The ratio of the present ages of two brothers is 1 : 2 and 5 years back, the ratio was 1 : 3. What will be the ratio of their ages after 6 years?

A) 1 : 4

B) 2 : 3

C) 3 : 5

D) 5 : 6

E) None of these

View Answer

Answer is C

Explanation:

Let us consider the present ages of the two brothers be x years and 2x years respectively.

Then, (x-6/2x-6) = (1/3) <=> 3(x – 6) = (2x – 6) <=> x = 12

∴ Required rate = (x + 6) : (2x + 6) = 18:30 = 3:5